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A close organ pipe of diameter 10 cm has...

A close organ pipe of diameter 10 cm has length 42 cm. the air column in pipe vibrates in its second overtone with the maximum amplitude `DeltaP_(o)`. The pressure amplitude at middle of pipe is

A

`(DeltaP_(@))/(2)`

B

`(DeltaP_(@))/(sqrt(2))`

C

`(sqrt(3)DeltaP_(@))/(2)`

D

`DeltaP_(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
here
`5(lamda)/(4)=42+0.3xx10implieslamda=36cm`
`therefore` pressure amplitude at middle of pipe is
`DeltaP=DeltaP_(@)|sinKx|=DeltaP_(@)|sin((2pi)/(36)xx24)|`
`=(sqrt(3)DeltaP_(@))/(2)`
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