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The momentum of alpha-particles moving i...

The momentum of `alpha`-particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :

A

`1.6xx10^(-20)km` m/s

B

`1.6xx10^(-21)kb` m/s

C

`1.6xx10^(-19)kg` m/s

D

`1.6xx10^(-18)kg` m/s

Text Solution

Verified by Experts

The correct Answer is:
B
`qvB=(mv^(2))/(R)`
`mv=qRB=1.6xx10^(-21)kg` m/sec
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