if `rho` is the density of the meterial of a wire and `sigma` is the breaking stress. The greatest length of the wire that can hang freely without breaking is

Options

A. `(2sigma)/(rhog)`
B. `(rho)/(sigmag)`
C. `(rhog)/(2sigma)`
D. `(sigma)/(rhog)`

Answer

D

Explanation

Maximum stress on the wire will be at highest point (at the point of suspension)
`thereforestress=("weight")/(A)=(Alrhog)/(A)=sigma`
`thereforel=(sigma)/(rhog)`