Both the strings shown in figure are mode of same material and have same cross-section. The pulleys are light the wave speed of a transverse wave in the string AB is `v_(1)` and in CD it is `v_(2)`. Then `v_(1)//v_(2)` is

Options

A. 1
B. 2
C. `sqrt(2)`
D. `1//sqrt(2)`

Answer

D

Explanation

`v=sqrt((T)/(mu)): " "V_(AB)=sqrt((T)/(mu))" ",V_(CD)=sqrt((2T)/(mu))`