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A battery of emf E(0) = 12 V is connecte...

A battery of emf `E_(0) = 12 V` is connected across a `4 m` long uniform wire having resistance `(4 Omega)/(m)`. The cells of small
emfs `epsilon_(1) = 2 V` and `epsilon_(2) - 4 V` having internal resistance `2 Omega` and `6 Omega` respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point `N`, the distance of point `N` from teh point `A` is equal to

A

`(1)/(6)m`

B

`(1)/(3)m`

C

`25cm`

D

`50cm`

Text Solution

Verified by Experts

The correct Answer is:
C

`4xxl(12)/(24)=(epsilon_(1)r_(2)-r_(1)epsilon_(2))/(r_(1)+r_(2))`
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