Forces acting on a particle moving in a straight line varies with the velocity of the particle as `F = (alpha)/(upsilon)` where `alpha` is constant. The work done by this force in time interval `Delta t` is :

Options

A. `(K)/(v^(2)).t`
B. `2Kt`
C. `Kt`
D. `(2Kt)/(v^(2))`

Answer

C

Explanation

Power P=F. `v=(K)/(v).v=K` =constant
`thereforeW=P.t=Kt`