An object O kept a distance a=10cm from the surface of a glass hemisphere `S_(1)` of radius R. `S_(2)` is another glass hemisphere kept side by side of same radius `R=5cm` as shown in figure `l_(1)` is the image formed due to object O `(b=6cm)`. Now if `S_(2)` is removed and `S_(1)` is kept at the same place and its flat surface is silvered then find te distance `l_(1)l_(2)` (where `l_(1)` si image formed by silvered `S_(1)` only) `(mu` glass =3/2)

Options

A. 10 cm
B. 12 cm
C. 11cm
D. 22 cm

Answer

D

Explanation

From symmetry `l_(1)l_(2)=2(b+R)=2(6+5)=22cm`