If a polarised light of intensity `l_(0)//2` is passed through two polariods `P_(1)` and `P_(2)` as shown in figure. Then the intensity of light observed by an observer on other side of `P_(2)` (if the polaroid `P_(1)` is rotated clockwise) as a funtion of angle `theta`.

Options

A.
B.
C.
D.

Answer

D

Explanation

`l=((l_(0))/(2))cos^(2)theta.sin^(2)theta=(l_(0))/(2)[(sin2theta)/(2)]^(2)=(l_(0))/(8)sin^(2)2theta`