A wedge of mass m, lying on a rough horizontal plane, is acted upon by a horizontal force `F_(1)` and another force `F_(2)`, inclined at an angle `theta` to the vertical. The block is in equilibrium, then minimum coefficient of friction between it and te surface is

Options

A. `(F_(2)sintheta)//(mg+F_(2)costheta)`
B. `(F_(1)costheta+F_(2))//(mg-F_(2)sintheta)`
C. `(F_(1)+F_(2)sintheta)//(mg+F_(2)costheta)`
D. `(F_(2)sintheta-F_(2))//(mg-F_(2)costheta)`

Answer

C

Explanation

`f=muN,(F_(1)+F_(2)sintheta)=mu(mg+F_(2)costheta)`
`mu=(F_(1)+F_(2)sintheta)/(mg+F_(2)costheta)`