A parent radioactive nucleus A (decay constant `lamda_(A))` converts into a radio-active nucleus B of decay constant `lamda_(b)`, initially, number of atoms of B is zero At any time `N_(a),N_(b)` are number of atoms of nuclei A and B respectively then maximum velue of `N_(b)`.

Options

A. `(lamda_(a)N_(a))/(lamda_(b))`
B. `(lamda_(b)N_(a))/(lamda_(a))`
C. `((lamda_(a)+lamda-(b))N_(a))/(lamda_(b))`
D. `(lamda_(b))/((lamda_(a)+lamda_(b)))N_(a)`

Answer

A

Explanation

`N_(b)` reaches maximum when activity of A will be equal to activity of B.
i.e., `lamda_(a)N_(a)=lamda_(b)N_(b)impliesN_(b)=(lamda_(a)N_(a))/(lamda_(b))`