Fundamental note of a closed pipe of lengt is l `f_(0)` at `0^(@)C` first overtone of te same pipe at `273^(@)C` is (assum there is no effect of temperature on te dimension of the pipe.)

Options

A. `3f_(0)`
B. `f_(0)`
C. `(3sqrt(2))f_(0)`
D. `3//sqrt(2)f_(0)`

Answer

C

Explanation

`f_(0)=(c)/(lamda)=(c)/(4(l+e))` and `(c)/(c_(0))=sqrt((273+theta)/(273))`
`thereforef_(0)^(')=(c_(0))/(4(l+e))sqrt(1+(theta)/(273))`
if temeprature is same, first overtone will be `3f_(0)` ,brgt `therefore` at `273^(@)C` first overtone is `3sqrt(2)f_(0)`.