Which of the following pair of compounds is expected to exhibit same colour in aqueous solution?

Options

A. `FeCl_(3),CuCl_(2)`
B. `VOCl_(2),CuCl_(2)`
C. `CoCl_(2),FeCl_(2)`
D. `FeCl_(2),MnCl_(2)`

Answer

B

Explanation

The colour of the transition metal ion is mainly attributed to d- transition take place because of the presence of unpaired electrons.
The metal ion having same number of unpaired electrons may give same colour in their aqueous solution. In `VOCl_(2)`,V^(IV)` ion having `3d^(1)` ion having `3d^(1)` configuration has one unpaired . SImilarly in `CuCl_(2)`, the `Cu^(2+)` ion having `3d^(9)` configuration also has one unpaired electron. SO `VOCl_(2)` and CuCl_(2)` are expected to exhibit same colour `i.e ` blue colour.
`Mn^(2+)` has five unpaired and `Fe^(2+)` has four unpaired electrons.