The oxidation number of Mn in the product of alkaline oxidative fusion of `MnO_2` is

Options

A. `3` electrons in neutral medium
B. `5` electrons in neutral medium
C. `3` electrons in alkaline medium
D. `5` electrons in acidic medium

Answer

ACD

Explanation

in acidic medium,`" "`MnO_(4)^(-)+8H^(+)+5e^(-) to Mn^(2+)+4H_(2)O`
`(V.f=5)`
`"in neutral//faintly alkaline medium"," " `MnO_(4)^(-)+2H_(2)O+3E^(-) to MnO_(2)+4OH^(-)`
(v.f.=3)
"In strong alkaline medium"," " MnO_(4)^(-)+e^(-) to MnO_(4)^(2-)`
(v.f.=1)