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How would you account for the following?...

How would you account for the following?
(i) The atomic radii of the metals of the third`(5d)` series of transition elements are virtually the same as those of the corresponding member of the second `(4d)` serie
(ii) The `E^(@)` value for the `Mn^(3+)//Mn^(2+)` couple is much more positive than that for `Cr^(3+)//Cr^(2+)` couple of `Fe^(3+)//Fe^(2+)` couple.
(iii) The highest oxidation state of a metal is exhibited in its oxides or fluoride.

Text Solution

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The correct Answer is:
(i) In the second transition series , the number of shells increases and so does the atomic size. However , in the third series `(5d series)` , the atomic size is more or loss the same . This is known as lanthanide contraction. This Is due to the poor shielding effect by f-electrons.
(ii) The large positive `E^(@)` value for `Mn^(3+)//Mn^(2+)` show that `Mn^(2+)` is much more stable than `Mn^(3+)` . This is because of the fact that `Mn^(2+)` has `3d^(5)` configuration. This means that the d-orbital is half -filled . Half -filled and fully-filled configuration are very stable. Thus , the third ionization energy of `Mn` will be very high.
(iii) Oxygen and fluorine act as strong oxidising agents from various metals . In other words, a metal exhibits highest oxidation state in its oxides and fluorides. For example , in `OsF_(6)` and `V_(2)O_(5)`, the oxidation states of `Os` and `V` are `+6` and `+5` respectively.
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How would you account for the following ? (i) The atomic radii of the metals of the third (5d) series of transition elements are virtually the same as those of the corresponding members of the second (4d) series. (ii) The E^(@) value for the Mn^(3+)//Mn^(2+) couple is much more positive than that for Cr^(3+)//Cr^(2+) couple or Fe^(3+)//Fe^(2+) couple. (iii) The highest oxidation state of a metal is exhibited in its oxide or fluoride.

How would you account for the following? (i)The atomic radii of the metals of the third (5d) series of trasition elements are virtually the same as those of the corresponding members of the second (4d) series. (ii)The E^(@) value for the Mn^(3+)//Mn^(2+) couple is much more positive than that for Cr^(3+)//Cr^(2+) couple or Fe^(3+)//Fe^(2+) couple. (iii)The highest oxidation state of a metal is exhibited in itsoxide or fluoride.

The atomic radii of the metals of the third (5d) series of transitions elements are virtually the same as those of the corresponding members of the second (4d) series. Explain.

Why is the E^(Theta) value for the Mn^(3+)//Mn^(2+) couple much more positive than that for Cr^(3+)//Cr^(2+) or Fe^(3+)//Fe^(2+)

How would you account for the following? (i) The atomic radii of the metals of the third (5d) series of transition elements are virtually the same as those of the corresponding member of the second (4d) serie (ii) Because oxygen and fluorine are highly electronegative elements and small in size.

Give reasons: E^0 value for Mn^(3+)//Mn^(2+) couple is much more positive than that for Fe^(3+)//Fe(2+) .

Why is the E^(@) values for Mn^(3+)//Mn^(2+) couple much more positive than for Cr^(3+) // Cr^(2+) or Fe^(3+)//Fe^(2+)

Why is the value for (Mn^(3+))/(Mn^(2+)) couple much more positive than that for (Cr^(3+))/(Cr^(2+)) or (Fe^(3+))/(Fe^(2+)) ? Explain

Why is the E^(Theta) value for the Mn^(3+)//Mn^(2+) couple much postive than for Cr^(3+)//Cr^(2+) or Fe^(3+)//Fe^(2+) ? Example

Wxplain why E^(@) for Mn^(3+)//Mn^(2+) couple is more positive than that for Fe^(3+)//Fe^(2+) (At. Nos. Mn=25,Fe=26)?

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