`1.6g of CH_(4)` contains same number of electrons as in :

Options

A. `4.48L` of `CH_(4)at NTP`
B. `6.02xx10^(22) "molecules of" CH_(4)`
C. `1 mol of Na`
D. `2.24 L` of `O_(2) at STP`

Answer

C

Explanation

`1.6g of CH_(4)` contains same ………….
`1.6g CH_(4)= 0.1mol CH_(4) implies 6.023xx10^(22) "Molecules" implies 10`
`xx6.02xx10^(22)` electrons
(1) `4.48L CH_(4) at N.T.P implies 0.2 mol CH_(4)`
`implies 20xx6.023xx10^(22)` electrons
(2) `6.02xx11^(22)` molecules of `CH_(4)`
`implies 10xx6.023xx10^(22)` electrons
(3) `1 mol Na^(+) implies 10xx6.02xx10^(23)` electrons
(4) `2.24 L of O_(2) at N.T.P. = 0.1 mol O_(2)`
`implies 6.02xx10^(22)` molecules of `O_(2) implies 16xx6.02xx10^(22)` electrons