`5.85 g NaCI` is dissolved in 1 litre water. The total number of ions of `Na^(+)` and `CI^(-)` in 1 mL of this solution will be :
A
`6.02xx10^(19)`
B
`1.2xx10^(22)`
C
`1.2xx10^(20)`
D
`6.02xx10^(20)`
Text Solution
Verified by Experts
The correct Answer is:
C
`5.85 g NaCI` is dissolved in ………… Number of moles of NaCI = Mass/Molar Mass `= 5.85//58.5` `= 0.1 mol` Number of ions `(Na^(+)+Cr)` in 1 L `= 2xx0.1xx6.02xx10^(23)` `= 12.04xx10^(22)` Number of ions in 1 mL `= 12.04xx10^(22)//1000` `1.2xx10^(20)`
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