A 100 watt buble emits monochromatic light of wavelength 400 nm. Then the number of photons emitted per seccond by the buble is nearly -
A
`2xx10^(20)`
B
`2xx10^(18)`
C
`2xx10^(16)`
D
`2xx10^(22)`
Text Solution
Verified by Experts
The correct Answer is:
A
A 100 watt buib emits …….. Power of the bulb = 100 watt `100 Js^(-1)` Energy of one photon `E = hv = hc//lambda` `= 6.62xx10^(-34)Jsxx3xx10^(8)ms^(-1)//400xx10^(-8)m` `= 4.96xx10^(-19)J` Number of photons emitted `= 100 Js^(-1)//4.96xx10^(-19)J` `= 2.01xx10^(20)s^(-1)`
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