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A mixture of HCI(g), PCI(3)(g) and PCI(5...

A mixture of `HCI(g), PCI_(3)(g)` and `PCI_(5)(s)` each have equal number of CI-atom then their molar ratio in the mixture is :

A

`1 : 3 : 5`

B

`1 : 1 : 1`

C

`15 : 2 : 3`

D

`15 : 5 : 3`

Text Solution

Verified by Experts

The correct Answer is:
D
A mixture of `HCI(g), PCI_(3)(g)` ………..
Let there are N atom of CI in each then moles of CI-atoms
`= (N)/(N_(A))`
`HCI: PCI_(3):PCI_(5)`
`(N)/(N_(A)): (1)/(3)(N)/(N_(A)):(1)/(5)(N)/(N_(A))`
`15:5:3`
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