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An organic compound has % C = 68.85, % H...

An organic compound has `% C = 68.85, % H = 4.92 and % O = 26.23` (by mass). Number of carbon atoms present in the Empirical Formula of it is ………….

A

`5`

B

`6`

C

`7`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
C
An organic compound has `% C` ………..
`C_((68.85)/(12)) H_((4.92)/(1)) O_((26.23)/(16)) or C_(3.5) H_(3)O`
`implies EF is C_(7)H_(6)O_(2)`
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