Energy of an emitted photon with wavelength `620 nm` is :
A
`1 eV`
B
`2 eV`
C
`1.5 eV`
D
`2.5 eV`
Text Solution
Verified by Experts
The correct Answer is:
B
Energy of asn emitted photon ……… `E_(ev)=(1240 eV-nm)/(lambda_(nm))` or `E_(ev) = (1240)/(620) = 2eV`
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