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In Se(Z = 34) how many electrons are pre...

In `Se(Z = 34)` how many electrons are present with `m_(l) = 2` ?

A

`20`

B

`4`

C

`2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
In `Se(Z= 34)` how many electrons …………….
`_(34)Se = [Ar]3d^(10), 4s^(2)p^(4)`
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