What is the increase in volume, when the temperature of `600 mL` of air increases from `27^(@)C` to `47^(@)C` under constant pressure?
A
`80 mL`
B
`40 mL`
C
`640 mL`
D
`500 mL`
Text Solution
Verified by Experts
The correct Answer is:
B
The increase in volume of a sample …………. `(V_(1))/(T_(1)) = (V_(2))/(T_(2))` so `V_(2) = (T_(2))/(T_(1)). V_(1) = (320)/(300)xx600 mL = 640 mL` so increment `= (640-600)mL = 40 mL`
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