The correct sequence which shown decreasiong order of the ionic radii of the elements is :
A
`AI^(3+)gt Mg^(2+)+Na^(+)gt F^(-)O^(2-)`
B
`Na^(+)gtMg^(2+)gtAI^(3+)gtO^(2-)gtF^(-)`
C
`Na^(+)gtF^(-)Mg^(2+)gtO_(2-)gtAI^(3+)`
D
`O^(2-)gtF^(-)Na^(+)gtMg^(2+)gtAI^(3+)`
Text Solution
Verified by Experts
The correct Answer is:
D
The correct sequence which shows ………… For isoelectronic species, ionic radii `prop (1)/("nuclear charge")` So, correct order of ionic radii is `8^(O^(2-))gt g^(F^(-))gt 11^(Na^(+))gt 12^(Mg^(2+))gt 13^(A//3+)`
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