What is the ratio of minimum to maximum wavelength of radiation emitted by electron when it jump from as higher state to ground state in `Li^(2+)` ion ?
A
`(1)/(4)`
B
`(8)/(9)`
C
`(3)/(4)`
D
`(1)/(9)`
Text Solution
Verified by Experts
The correct Answer is:
C
What is the ratio of ………….. `(((1)/(lambda_(max))))/(((1)/(lambda_(min))))=(R(3)^(2)[(1)/(1^(2))-(1)/(2^(2))])/(R(3)^(2)[(1)/(1^(2))-(1)/(oo^(2))]) = 3//4` `:. (lambda_(min))/(lambda_(max)) = (3)/(4)`
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