For chromium element, how many electrons can have `n+l+|m|=4` , with clockwise spin in ground state ?

Options

A. `2`
B. `3`
C. `4`
D. `6`

Answer

B, C

Explanation

For chromium element, how many ………..
`._(24)Cr-1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(1)3d^(6)`
Only `2p, 3p` and `4s` orbital satisfies the relation `n+l+|m| =4`
for `2p` orbital `implies 2 e^(-)` , `(m= +- 1)`
for `3p` orbital `implies 1e^(-)`
for `4s` orbital `implies 1e^(-)` single `e^(3)` may have clockwise or anticlockwise spin.
`:.` no.of electrons may be `= 3 or 4`