A mono-atomic gas `X` and an diatomic gas `Y` both initially at the same temperature and pressure are compressed adiabatically from a volume `V` to `V//2`. Which gas will be at higher temperature?
A
`X`
B
`Y`
C
same for both
D
can't say
Text Solution
Verified by Experts
The correct Answer is:
A
A mono atomic gas `X` and a ……….. `T_(1)V_(1)^(y-1)=T_(2)V_(2)^(y-1)` `:. (T_(2))/(T_(1)) = ((V_(1))/(V_(2)))^(y-1) = 2^(y-1)` Since `gamma` is more for the gas `X` , the temperature will also be mmore for it `:. (1)` .
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