An unknown gaseous hydrocarbon and oxygen gas are mixed in volume ratio `1:7` respectively and exploded. The resulting mixture upon cooling occupied a volume of `V mL`, half of which got absorbed in aq. `KOH` (absorbed `CO_(2)`) and the remaining half was absorbed in alkaline pyrogallol solution (absorbs `O_(2)`) . Assuming all volumes to be measured under identical conditions :
A
The molecular formula of hydrocarbon can be `C_(2)H_(6)`
B
The resulting mixture obtained after cooling contains `50% O_(2)` and `50% CO` by mole.
C
The molecular formula of hydrocarbon can be `C_(3)H_(4)` .
D
Molecular mass of hydrocarbon is definitely less than `28 u` .
Text Solution
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The correct Answer is:
C
An unknown gaseous …………. `{:(,C_(x)H_(y)+,(x+(y)/(4))O_(2)rarr,xCO_(2)+(y)/(2)H_(2)O(l)),(i,a,7a,0),(f,0,7a-(x+(y)/(4))a,xa):}` Given : `7a - (x+(y)/(4))a = xa` `:. 8x +y = 28` Only `C_(3)H_(4)` hydrocarbon satisfies the above relation.
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