The volume of acetylene at `NTP` produced by reaction to `50gm` of `CaC_(2)` with water is : `CaC_(2)+H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
A
`10L`
B
`17.5L`
C
`26.25L`
D
`35L`
Text Solution
Verified by Experts
The correct Answer is:
B
The volume of acetylene ……. `CaC_(2)+2H_(2)OrarrCa(OH)_(2)+C_(2)H_(2)` `50gm` `n_(CaC_(2) = (50)/(64) = n_(C_(2)H_(2))` Volume `= (50)/(64)xx22.4 L = 17.5L`
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