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By doing which of the following the Ruth...

By doing which of the following the Rutherford's closest distance of approach (calculated by using alpha-particles) decreases ?

A

By increasing the initial speed of alpha-particles

B

By decreasing the kinetic energy of alpha-particles

C

By using silver foil `(Z = 47)` in place of gold foil `(Z = 79)`

D

By using metal foil `(Z gt 79)` in place of gold foil `(Z = 79)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`R = (4KZe^(2))/(m_(alpha)v_(alpha)^(2))`
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