A particle is moving along straight line whose position `x` at time `t` is described by `x = t^(3) - t^(2)` where `x` is in meters and `t`is in seconds . Then the average acceleration from `t = 2` sec. to `t = 4` sec, is :

Options

A. `16 m//s^(2)`
B. `18 m//s^(2)`
C. `22 m//s^(2)`
D. `10 m//s^(2)`

Answer

A

Explanation

`v = (dx)/(dt) = 3t^(2) - 2t`