If pulley is ideal and string is massless then reading of weighing machine is `(5x)/(3)kg` then calculate `x. : (g = 10 m//s^(2))`

Answer

5

Explanation

`a = (80g - 0.5 xx 10 xx 10)/(90) = (25)/(3)`
`-N + 500 = 50((25)/(3))`
`N = 500 - 50(25)/(3) = 50[(10 - 25)/(3)] = (250)/(3)N = (25)/(3)Kg wt`