Initially a man and a car both are stationary and situated at a distance of `100 m`. Noq both starts moving simltaneously in the same direction as shown in figure. Then :

Options

A. man has to move `200 m` to catch the car
B. car will move `100 m` when man catches it
C. time taken by man to catch the car is `10sqrt(2)` sec
D. man can not catch the car

Answer

A, B, C

Explanation

`x = (1)/(2) 2xt^(2)`
`x - 100 = (1)/(2).1t^(2)`
`(x)/(2) = 100`
`x = 200 m`
`200 = t^(2)`
`t = 10sqrt(2) sec`.