A solid sphere with angular velocity `omega_(0)` is dropped on a rough surface with coefficient of frication `'mu'` froma height `'h'`. If the collision with ground is perfectly inelastic if the velocity of centre of mass just after the impact is `musqrt((xgh)/(3))` then value of `x` would be :

Answer

6

Explanation

The collision is perfectly inelastic
Hence , `intNdt = msqrt(2gh)`
and the linear impulse
`int mu Ndt = mv`
`mu m sqrt(2gh) = mv`
`v = mu sqrt(2gh)`