`1` mol of an ideal gas undergoes different thermodynamical process in `P-V` digram given below :

If temperature at point `C` is `T K` then :

Options

A. Temperature at point `A` is `T K`.
B. Temperature at point `A` is `2T K`.
C. Temperature at point `B` is `T K`.
D. Temperature at point `B` is `2T K`.

Answer

B, D

Explanation

Process `CA` is isochoric `P_(A) = 2P_(C)` so `T_(A) = 2T`
And process `AB` is isothermal `T_(A) = T_(B) = 2T`