`N_(2)O_(3)` dissociates into `NO` and `NO_(2)`. At equilibrium pressure of `3 atm` , all three gases were found to have equal number of moles in a vessel. In another vessel, equimolormixture of `N_(2)O_(3), NO` and `NO_(2)` are taken at the same temperature but at an initial pressure of `9 atm` then find the partial pressure of `NO_(2)` (in `atm`) at equilibrium in second vessel!
`N_(2)O_(3)(g) hArr NO(g) + NO_(2) (g)`

Answer

2

Explanation

`N_(2)O_(3)(g)hArrNO(g) + NO_(2)(g) , K_(P) = 1`
`{:("Initial",3,3,3),("Pressure",,,),(at eq.,3+P,3-P,3-P):}`
`K_(P) = ((3-P)^(2))/((3+P)) = 1`
Solving this `P = 1 atm`