For the dissociation
`A_(2)B_(3)hArr2AB(g) + (1)/(2)B_(2)(g)`
If, `M =` Molecular mass of `A_(2)B_(3)(g)`
`D =` Vapour density of equilibrium mixture
`P^(@) =` Initial pressure of `A_(2)B_(2)(g)`
then, identify the correct statement(s) :

Options

A. Equilibrium pressure can be expressed as `(2P^(@)D)/(M)`
B. Equilibrium pressure can be expressed as `(2P^(@)M)/(2D)`
C. Degree of dissociation of `A_(2)B_(3)(g)` can be expressed as `(M - 2D)/(3D)`
D. Increase in temperature will increase the magnitude of `D`

Answer

C

Explanation

`alpha = (d_(1) - d_(@))/((n-1)d_(0)) = ((M)/(2) - D)/((2.5 - 1)D)`
`= (M - 2D)/(3D)`
`A_(2)B_(2)(g) hArr 2AB(g) , + (1)/(2)B_(2)(g)`
`1.((M - 2D)/(3D)) + 2((M - 2D)/(3D)) + ((M - 2D)/(3D)) + ((M - 2D)/(6D)) = 1 + (M - 2D)/(2D)`
`(P^(@))/(P_(f)) = (1)/(1 + (M - 2D)/(2D))` or `P_(f) = (P^(@)M)/(2D)`