`1` mol of an idel gas is allowed to expand isothermally at `27^(@)C` till its volume is tripped. If the expansion is carried out reversibly then select the correct option(s) : `(R = (25)/(3)(J)/("molK"),log3=0.48)`

Options

A. `q _(sys) = 2763 J//mol`
B. `DeltaS_(sys.) = 7.21 J//K` mol
C. `DeltaS_(universe) = 0`
D. `DeltaS_(surr.) = -9.21 J//K` mol

Answer

A, C, D

Explanation

In isothermal reversible process
`DeltaS_(says) = 2.303 nR log'(V_(2))/(V_(1))`
`DeltaS = (q_(rev))/(T)`
`DeltaS_(universe) = 0`