`M(OH)_(X)` has `K_(SP) 4xx10^(-12)` and solubility `10^(-4) M`. The value of `x` is:
A
`1`
B
`2`
C
`3`
D
`4`
Text Solution
Verified by Experts
The correct Answer is:
B
`{:(M(OH)_(x)hArr,M^(+x)+,xOH^(-)),(,s,xs):}` `K_(sp) = S.(XS)^(x) = X^(x).S^((x+1)) = 4 xx 10^(-12)` given `() S = 10^(-4)` `:. x = 2`
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