The most stable resonating structure is

Options

A. `H_(2)N-overset(o+)(CH)-CH=CH-OCH_(3)`
B. `H_(2)overset(o+)N=CH-CH=CH-OCH_(3)`
C.
D. `NH_(2)-overset(o+)(C)H-overset(ɵ)(C)H-CH=overset(o+)(O)CH_(3)`

Explanation

To determine the most stable resonating structure among the given options, we can follow these steps:

### Step 1: Analyze the Resonating Structures
We need to look at each of the given resonating structures and identify the distribution of charges and the presence of double bonds.

### Step 2: Evaluate Charge Distribution
- **Positive Charge**: A positive charge should be on a less electronegative atom to increase stability.
- **Negative Charge**: A negative charge should ideally be on a more electronegative atom.

### Step 3: Count the Number of Charges
The stability of a resonating structure increases with fewer charges. Therefore, we should count the total number of charges in each structure:
- **Option A**: Count the charges.
- **Option B**: Count the charges.
- **Option C**: Count the charges.

### Step 4: Assess the Number of Double Bonds
More double bonds generally indicate greater stability due to increased resonance. Check how many double bonds are present in each structure:
- **Option A**: Identify the number of double bonds.
- **Option B**: Identify the number of double bonds.
- **Option C**: Identify the number of double bonds.

### Step 5: Compare the Structures
Now, compare the structures based on:
- The number of charges (fewer is better).
- The position of positive and negative charges (less electronegative atom for positive charge).
- The number of double bonds (more is better).

### Step 6: Conclusion
Based on the analysis:
- If Option A has one charge and one double bond, Option B has one charge and two double bonds, and Option C has three charges, then Option B is the most stable structure due to having fewer charges and more double bonds.

### Final Answer
Option B is the most stable resonating structure.

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