The producet of the reaction of alcoholic silver nitrite with ethyl bromide is :
A
Nitroethane
B
Nitroethane and ethyl nitrite
C
Ethyl nitrite
D
Ethane
Text Solution
Verified by Experts
The correct Answer is:
A
(1) `C_(2)H_(5)+Ag-O-N=Orarrunderset("Nitre ethane")(C_(2)H_(5)-N)overset(O)underset(O)+AgBr^(-)` `Ag-O-N = 0` is a covalent compound. Therefore, attack to nuclephile occurs through Nitrogen atom. Hence, nitroethane is formed.
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