A vessel contains `0.5g` of hydrogen and `0.8g` of oxygen. The volume of vessel is `(5)/(28)m^(3)` while its temperature is maintanied at `300K`. Find the pressure of the mixture. (Assuming no reaction takes place between hydrogen and oxygen) `(M_(H_(2)) =2 , M_(O_(2)) = 32 & R = (25)/(3) J//mol-K)`

Answer

`3850N//m^(2)`

Explanation

`n_(1) = (m)/(M) = (0.5)/(2) = (1)/(4)` mole
`n_(2) = (0.8)/(32) = (1)/(40) "mole" , (n_(1)+n_(2)) = (11)/(40)`mole
`P = ((n_(1)+n_(2))RT)/(V) =(((11)/(40))xx((25)/(3))xx300xx28)/(5)`
`= 3850N//m^(2)`