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If gamma be the ratio of specific heats ...

If `gamma` be the ratio of specific heats `(C_(p) & C_(v))` for a perfect gas. Find the number of degrees of freedom of a molecules of the gas?

Text Solution

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The correct Answer is:
`(2)/(gamma-1)`
`gamma = (C_(P))/(C_(V)) = (((f+2)/(2))R)/((f)/(2)R)`
`= (f+2)/(f) =1+(2)/(f), f = (2)/(gamma-1)`
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