If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is

Answer

`(3)/(2)`

Explanation

`gamma_(mix) = (C_(Pmix))/(C_(Vmix)) = (1xx(5)/(2)R+1xx(7)/(2)R)/(1xx(3)/(2)+1xx(5)/(2)R)=(3)/(2)`