A Carnot engine works as a refrigerator in between `250K` and `300K`. If it acquires `750` calories form heat source at low temperature, then what is the heat generated at higher temperature (in calories)?

Answer

`900` Calories

Explanation

`eta = (Q_(2))/(Q_(1)-Q_(2)) = (T_(2))/(T_(1)-T_(2)) rArr (750)/(Q_(1) - 750) = (250)/(300-250)`
`Q_(1) = 900` Calories