In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas:

Options

A. is positive
B. is negative
C. is zero
D. may be positive

Answer

B

Explanation

`P alpha (1)/(V^(2)) rArr P = (k)/(V^(2)) rArr PV^(2) = k`
`rArr PV. V = k rArr nRTV = k rarr TV = k_(1)`
Since temperature increases therefore volume decreases or work done by the gas is negative.