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The value of C(p) - C(v) is 1.09R for a ...

The value of `C_(p) - C_(v)` is `1.09R` for a gas sample in state `A` and is `1.00R` in state `B`. Let `A_(A),T_(B)` denote the temperature and `p_(A)` and `P_(B)` denote the pressure of the states `A` and `B` respectively. Then

A

`p_(A) lt p_(B)` and `T_(A) gt T_(B)`

B

`p_(A) gt p_(B)` and `T_(A) gt T_(B )`

C

`p_(A) = p_(B)` and `T_(A) lt T_(B)`

D

`p_(A) gt p_(B)` and `T_(A) lt T_(B)`

Text Solution

Verified by Experts

The correct Answer is:
D
For an ideal gas
`C_(P) - C_(V) = R , if C_(P) - C_(V) = 1.09R`
or `p_(A) gt p_(B) T_(A) lt T_(B)`
Then gas will be real. Thus pressure is high and temperature is low of real gas.
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