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4 moles of H(2) at 500K is mixed with 2 ...

`4` moles of `H_(2) at 500K` is mixed with `2` moles of `He` at `400k`. The mixture attains a temperature `T` and volume `V`. Now the mixture is compressed adiabatically to a volume `V'` and temperature `T'`. If `(T')/(T) = ((V)/(V'))^(n)`, find the value of `13n`.

A

`4`

B

`6`

C

`5`

D

`13`

Text Solution

Verified by Experts

The correct Answer is:
B
`TV^(gamma-1) = C`
`gamma - 1 = n`
`n = (6)/(13)`
`gamma =(4xx(7)/(2)R +2xx(5)/(2)R)/(4xx(5)/(2)R+2xx(3)/(2)R) =(19)/(13)`
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