When `2g` of gas `A` is introduced into an evacuated flask kept at `25^(@)C` the presusre is found to be `1atm`. If `3g` of another gas `B` is then added to the same flask the total pressure becomes `1.5 atm`. The ratio of

Answer

3

Explanation

From `pV = nRT`
`1 xx V = (2)/(M_(A)) RT ……..(i)`
`1.5 xx V = ((2)/(M_(A))+(3)/(M_(B)))RT ........(ii)`
From (i) & (ii)
`rArr 1.5 =1+(3)/(2) (M_(A))/(M_(B)) rArr (M_(A))/(M_(B)) = (1)/(3)`