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A thermally isolated vessel contains 100...

A thermally isolated vessel contains `100`g of water at `0^(@)C` when air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass at `0^(@)C=2.10xx10^(6) j//kg` and latent heat of fusion of ice `=3.36xx10^(5) j//kg`.

A

`86.2 g`

B

`13.8 g`

C

`76.2 g`

D

`65.6g`

Text Solution

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The correct Answer is:
A
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A thermally isolated vessel contains 100g of water at 0^(@)C . When air above the water is pumped out, some of the water freezes and some evaporates at 0^(@)C itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at 0^(@)C=2.10xx10^(6)J//kg and latent heat of fusion of ice =3.36xx10^(5)J//kg .

A thermally isolated vessel is maintained inside at 0^@C and contains 200 g of water. When the air above the water is pumped out, some of the water freezes while rest of it evaporated at 0^@C itself. Determine the mass of water that freezed. Take, Latent heat of vapourisation of water at 0^@C = 2.19 xx 10^3 J//g Latent heat of fusion of ice = 3.36 xx 10^2 J//g

What is meant by saying that the latent heat of fusion of ice is 3.34 xx 10^(5)J//kg ?

A thermally insulated vessel contains 150g of water at 0^(@)C . Then the air from the vessel is pumped out adiabatically. A fraction of water turms into ice and the rest evaporates at 0^(@)C itself. The mass of evaporated water will be closest to : (Latent heat of vaporization of water =2.10xx10^(6)jkg^(-1) and Latent heat of Fusion of water =3.36xx10^(5)jkg^(-1) )

A thermal insulated vessel contains some water at 0^(@)C . The vessel is connected to a vaccum pump to pum out water vapour. This results in some water getting frozen. It is given latent heat of vaporization of water at 0^(@)C = 21 xx 10^(5) J//kg and latent heat of freezing of water =3.36 xx 10^(5) J//kg . the maximum percentage amount of water vapour that will be solidified in this manner will be:

At 0^@C a thermally isolated container has 200 g of water. When air above water is pumped out, then some of water evaporates and some of it freezes. What will be the mass of ice formed on freezing when there will be no water left in container? Latent heat of vaporisation of water = 2.2 xx 10^6 J/kg and latent heat of fusion of ice = 3.37 xx 10^5 J/kg.

Find the final temperature and composition of the mixtue of 1 kg of ice at 0^(@)C and 1.5 kg of water at 45^(@)C . Given that specific heat of water is 4200 J/kg and latent heat of fusion of ice is 3.36xx10^(5)J//kg

A closely thermally insulated vessel contains 100 g of water at 0^@C . If the air from this vessel is rapidly pumped out, intensive evaporation will produce cooling and as a result of this, water freeze. How much ice will be formed by this method? If latent heat of fusion is 80 cal//g and of evaporation 560 cal//g . [ Hint If m gram ice is formed, mL_(f)=(100-m)l_(v) ]

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RESONANCE-CALORIMETRY AND THERMAL EXPANSION-Exercise
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