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A hot black body emits the enegy at the ...

A hot black body emits the enegy at the rate of 16 `Jm^-2s^-1` and its most intense radiation corresponds to 20000`Å`. When the temprerature of this body is further increased and its most intense radiation corresponds to `10000Å`, then find the value of energy radiated in `Jm^-2s^-1`.

Text Solution

Verified by Experts

Wein's displacement law is:
`lambda_(m) T = b`
i.e. `T prop (1)/(lambda_(m))`
Here, `lambda_(m)` becomes half.
`:.` Temperature doubles.
Also `e = sigma T^(4)`
`rArr (e_(1))/(e_(2)) = ((T_(1))/(T_(2)))^(4) rArr e_(2) = ((T_(2))/(T_(1)))^(4) e_(1) = (2)^(4) 16`
`=16.16 = 256 J m^(-2) s^(-1)`
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